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Aaron Rodgers named NFC Offensive Player of the Week

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Rodgers’ 246-yard, three-touchdown effort earned him his first Player of the Week honor of 2016.

NFL: Seattle Seahawks at Green Bay Packers Jeff Hanisch-USA TODAY Sports

Aaron Rodgers tore apart the Seattle Seahawks this past Sunday, and it turns out plenty of people noticed. For his outstanding performance, the Green Bay Packers quarterback earned Week 14’s NFC Offensive Player of the Week honors, announced by the NFL Wednesday.

Rodgers played his best game of the season, starting off 12 of 13 for 202 yards and two touchdowns, good for a perfect 158.3 passer rating. He barely cooled off over the remainder of his snaps, finishing with a season-high 78.3 completion rate and a 150.8 rating.

The Seahawks had no answer for the dimes Rodgers dropped to Davante Adams, one of which went for a 66-yard score on the third play from scrimmage. They also struggled to contain Jordy Nelson, who scored two touchdowns off breaking routes. Rodgers took advantage of all of it, giving the Packers their most impressive blowout win in several seasons.

The rest of the NFC Player of the Week honors went to Atlanta Falcons pass rusher Vic Beasley and New York Giants punter Brad Wing. Pittsburgh Steelers running back Le’Veon Bell, Cincinnati Bengals defensive tackle Geno Atkins, and Kansas City Chiefs returner Tyreek Hill received the AFC nods.

Jason B. Hirschhorn is an award-winning journalist and Pro Football Writers of America member. He covers the NFL for Sports on Earth and SB Nation. He also serves as the senior writer and editor for Acme Packing Company, a Green Bay Packers blog.