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Aaron Jones earns NFC Offensive Player of the Week award for second time in 2019

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Jones’ huge day against the Chiefs gets him the award for the second time in four weeks.

Green Bay Packers v Kansas City Chiefs Photo by Peter G. Aiken/Getty Images

In week five, Green Bay Packers running back Aaron Jones scored four touchdowns against the Dallas Cowboys. He rushed for 107 yards that day and caught seven passes for 75 yards to set a career-high in total yards of offense, earning NFC Offensive Player of the Week for his efforts.

Three weeks later, Jones surpassed that yardage total and earned the same award for the second time in less than a month.

Jones exploded again against the Kansas City Chiefs in week eight, running the ball 13 times for 67 yards and catching seven passes for 159 yards and two touchdowns. On Wednesday, the NFL named him as player of the week. This is Jones’ third such honor, as he received the award in week five of the 2017 season as well (coincidentally, for another great performance against the Cowboys).

Jones now leads the NFL in touchdowns with 11, eight on the ground and three through the air. He also ranks sixth in the league in total yards from scrimmage and sits third among all running backs in PPR fantasy points.

October has been the month of the Packer for this award. Besides Jones’ two honors, Aaron Rodgers also got one after the game against the Raiders in week seven saw him put up a perfect passer rating with six total touchdowns. The only non-Packer to win the award in October was Cardinals quarterback Kyler Murray, who threw for 340 yards and three touchdowns against the Atlanta Falcons in week six.